How to differentiate between different types of relationships?

Scripting
1

My objective is to fetch all incoming links and outgoing links to and from any class. These links could include exchange items, associations, compositions, generalizations etc.

I use the semantic browser for simple models but for a general solution or larger models, it is impractical. For example, “Roles”, “Typing Elements” etc. are not consistent enough. It is hard to identify the parent and child of an element.

I tried fetching all contents of the data package folder but I am unable to differentiate between the different types of relationships. For example, in the following image, vce is a composition and class 3 is an aggregation.

image
image213×207 2.36 KB

How can I identify the type, parent (outgoing link) and child (incoming link) in P4C?

2

I think some extends are missing for the Property class:

But you can use the Java API:

for property in se.get_all_contents_by_type(Property):
    prt = property.get_java_object()
    print(prt.getName(), "type:" + prt.eClass().getName(), prt.isUnique(), prt.isIsReadOnly(), prt.getAggregationKind().getName())

To get the list of all EStructuralFeatures of the Property EClass you can use the following AQL expression in the Sirius interpreter view:

aql:information::Property.eAllStructuralFeatures

You will probably need to select a CapellaElement before getting the result.

If you need to check the type of an element against an EClass you can use:

roleECls = get_e_classifier("http://www.polarsys.org/capella/core/oa/" + capella_version(), "Role")
roleECls.isInstance(prt)

You can also get an enum literal:

association = get_enum_literal("http://www.polarsys.org/capella/core/information/" + capella_version(), "AggregationKind", "ASSOCIATION")
prt.getAggregationKind() = association

For a complete description of Capella metamodels (EPackages) you can have a look here.
I hope this will get you started with your script.

1 Like